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Rock Paper Scissors by number of bets (Bot proof)

Rock Paper Scissors by number of bets (Bot proof)
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Description

Rock smashes Scissors
Paper covers Rock
Scissors cut Paper

The bet counting will be done in a way to prevent a bot from changing the outcome at the last second, so placing a bunch of bets all at once will only count as one bet.

Decision Logic

Step 1: The two options with the largest number of bets will be compared to each other with the following caveat:
THIS IS IMPORTANT: Any bets on the same option placed within the same minute will only count as ONE bet.
Note that volume DOES NOT matter here, just number of bets. (If there is a tie, the option with the most recent bet will lose.)

Step 2: The final two options will be compared with the following rules:
Rock beats Scissors
Paper beats Rock
Scissors beats Paper

12:49AM, Aug 18, 2014 UTC

1:00AM, Aug 23, 2014 UTC

1:30AM, Aug 23, 2014 UTC

CANCELLED

This bet has been cancelled!

Reason: Only one person bet on it. Next time, try sharing it with others!

Rock
Volume:0.0000
0
# of Bets:0
Paper
Volume:0.0000
0
# of Bets:0
Scissors
Volume:0.0000
0
# of Bets:0

Discussion

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Avalon 11:20PM, Aug 18, 2014 UTC
@sirlanka The option with the most recent bet would lose. Eg: if you have Rock - 8, Sci - 7, Paper - 7, and Paper had a more recent bet than Sci then Rock competes with Scissors (and wins)
sirlanka 6:15PM, Aug 18, 2014 UTC
Ok, I see. And if the bottom two draw? Is the most recent of them out and the other two compete?
Avalon 4:44PM, Aug 18, 2014 UTC
@sirlanka - "(If there is a tie, the option with the most recent bet will lose.)". So if there's a 3 way tie, the losing option is the one with the most recent bet, and the other 2 compete.
sirlanka 5:51AM, Aug 18, 2014 UTC
It is unclear what happens is one alternative gets most number of bets and the other two split. It is unclear what happens if all three options get the same number of bets.

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